how to turn 2x^2-10+8y=16x-2y^2 so it follows this form: (x-a)^2+(y-b)^2=r^2?
It is for a cirkel in vectorfuctions.

Question

how to turn 2x^2-10+8y=16x-2y^2 so it follows this form: (x-a)^2+(y-b)^2=r^2?
It is for a cirkel in vectorfuctions.

campbell_st · Answer

use complete the square but 1st divide each term by 2

then rewrite the equation

$$x^2 - 8x + y^2 + 8y = 5$$

complete the square for the terms in x by (-8/2)^2 being added to both sides

complete the square for the terms in y by adding (8/2)^2 to both sides

then it will be 

(x +(-8/2))^2 + (y + (8/2))^2 = 5 +(-8/2)^2 + (8/2)^2

just simplify for your answer

anonymous · Answer

Close... when you divided by two... you left 8y.  It should be 4y.  Then subsequent fixes follow.

campbell_st · Answer

dang...simplify this 

 (x + (-8/2))^2 + (y + (4/2)^2 = 5 + (8/2)^2 + (4/2)^2

anonymous · Answer

Perfecto!