Question

integral of 10^x from -1 to 1

Answer 1

misread sorry i got you...

Answer 2

integral of a^x is a^x/log a
does this help?

Answer 3

\[\int\limits_{}^{}a^xdx=\frac{a^x}{\log a}\]

Answer 4

Yes that does! How do you know that formula?

Answer 5

Because
\[ \frac{d}{dx} a^x = a^x \log(a) \]

Answer 6

the way I remember it is
1) I know how to do
\[\int\limits e^{ax} dx\]
2) I know 10 is e to some power a : \(10= e^a \)
3) also \( 10^x = (e^a)^x= e^{ax} \)

4) The "a" to make e^a= 10 is ln(10) (log base e of 10)

putting it together
\[ \int e^{ln(10)x} dx \]
where ln(10) is just a constant