The quotient of a number and 2 is the same as the difference of the number doubled and 3. What is the number?
My bad. LOL. I wrote the right thing. accidentally deleted it.
Let x be the number. \[{x \over 2}=2x-3\] solve for x.
how would I solve for x? would I do 2x*2?
hmm...
Yes, you do 2x*2. I'm sorry. I'm really tired now. Way past bedtime.
\[{x \over 2} \times 2= 2(2x-3)\]
that's ok, I hope I'm not a pain. I just don't fully understand it thats all
No worries. I enjoy explaining.
Which part do you not understand? The question or how to solve for x?
2x=4x-6?
almost correct. except that there is no 2x.
oh ooops, 4x=4x-6?
For example, when you multiply 1/2 by 2, you get 1. (because the 2s cancel out each other) In this case, x/2 is multiplied by 2, you get x.
So would that make it 4 1/2?
May I ask which syllabus are you learning?
you are*
I do school online, so I get random things thrown at me to figure out
I totally understand. I'm online schooled too. ;)
So I'm guessing, American syllabus then? (Cause american and british syllabus have different ways of teaching algebra.)
Oh...yes American Syllabus
Alright then. This is the equation that your question is asking you to solve: \[{x \over 2}=2x-3\] First, you must get rid of the 2 below the x (on the right side of the equation.)
To do that, you multiply the number by itself because (as an example) 1/2 multiplied by 2 is somewhat like 2 divided by 2. When you divide 2 by 2, you get 1. Still following?
Yes I am.
\[{1 \over 2} \times 2={2 \over 2}=1\]
okay. so in this case, we have x, which has an invisible coefficient of 1, so you treat it like a 1.
oh ok
so instead of writing 1, you write x instead. Like in this case, \[{x \over 2} \times 2 ={2x \over 2}=x\]
anyways, when you multiply the 2 on one side, you have to multiply the 2 on the other side too, that's how you get... \[x=4x-6\] still following?
Yes (:
okay, now you want to isolate x to one side so you minus 4x from both sides. \[x-4x=4x-4x-6\] What do you get now?
3x=6?
correct! (you're one step ahead, but that's good so, good job!) Now, you want to find x so you divide both sides by 3. \[{3x \over 3}={6 \over 3}\] can you solve this one? :)
x/2 ?
Do one side at a time.
\[{3x \over 3}=?\]
oh... 3/3=0 so x. and 6/3=2 so 2? x=2?
yes!
Just to correct you. 3/3 is actually 1.
but your answer is correct anyway. :)
Yay!! Thank You so much for the help!!!
You're welcome! Just keep doing practices and you'll get the hang of it in no time!
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