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a silver ball weighing 50g is removed from a furnace and dropped into a 350g of water at 0 degree celcius. if the equilibrium temperature is 10 degree celcius and the specific heat capacity of platinum is 230Jkg-1 degree celcius-1, what is the temperature of the furnace? neglect the effect of the mass of the calorimeter...
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\[Q=mc \Delta T=mc(T_f-T_i)\]At equilibrium the energy exchanged will be equal:\[mc\Delta T (furnace)+mc\Delta T(water)=0\]\[(0.050kg)(230J/kgC)(10C-T_i)+(0.350kg)(4186J/kg)(10C)=0\]Now just solve for Ti to get the temperature of the furnace.
thank you so much... :D
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