Question

find the limit of

Answer 1

\[\lim_{x \rightarrow 1+} (1)\div(x ^{2}-1)\]

Answer 2

since \(x\to1+\) this means that \(x>1\) so \(x^2>1\) or \(x^2-1>0\)

Answer 3

\[ \large \lim_{x\to1+}\frac{1}{x^2-1}=\frac{1}{1-1}=\frac{1}{0+}= \]

Answer 4

this is \[\infty\] correct

Answer 5

notice that \(x^2-1>0\)
so, though x^2-1 turns zero, it does so with positive numbers !!!!

Answer 6

ok thanks

Answer 7

\[ \large =+\infty \]