Question

state the gernal term. t4=35 and common difference is -12

Answer 1

\(t_4=35\)
\(t_3=47\)
\(t_2=59\)
\(t_1=62\) i think, because the common difference is 12

Answer 2

so in general \(t_n=73-12n\) i suppose, although maybe this is not what you want

Answer 3

answer says it should be tn=83-12n but i dont know how to get that

Answer 4

cause i messed up sorry

Answer 5

i took the fourth term and kept adding 12 to count down, but my addition was sloppy

Answer 6

\(t_4=35\)
\(t_3=35+12=47\)
\(t_2=47+12=59\)
\(t_1=59+12=71\)
\[t_0=71+12=83\]

Answer 7

subtract 12 each time, the \(n\)th term will look like \(t_n=83-12n\)

Answer 8

thanks :)