Question

Can anyone help with solving equations with absolute values?

Answer 1

sure whats the problem?

Answer 2

Ok..
1.) 2|f| - 3|e| + |f|squared..........f=-3 and e=-2
2.)[1-12-(-3)]-|-15-18|
Also this problem without absolute values:
3.) 16a cubed -4a squared + 64a + 36 all over 4

Can u explain to me the rule about solving equations with absolute values?

Answer 3

Please help...really confused

Answer 4

All that an absolute value does is tell you how far from zero you are.
Therefore, |-7|=7 AND |-a|=a , when a>0

Answer 5

in part 1 you have to substitute the values for f into the expression. Switch f with -3 and switch e with -2

Answer 6

But when I'm solving with absolute values, do I keep the negative sign in the absolute value or do I switch it to positive immediately?

Answer 7

i am doing it in many steps, in this case keep both the absolute value symbols and the negative signs inside of them

Answer 8

\[2*|f|-3*|e|+|f|^2\]
\[2*|-3|-3*|-2|+|-3|^2=2*3-3*2+3*3\]

Answer 9

Thank you and can you show me all three problems that I posted... because I understand it better when u go step by step so thank u!!

Answer 10

For part two you evaluate the stuff inside of the absolute values first. Once you do that you make sure that whatever is inside of the absolute value becomes positive.

Answer 11

Can u help solve it cuz for some reason I keep getting the wrong answer.

Answer 12

Part 2
\[[1-12-(-3)]-|-15-18|=|-8|-|-33|\]

Answer 13

Can you do it from there?

Answer 14

wait from {1-12-(-3)}... How do you do this correctly in order?

Answer 15

completely evaluate the inside of the absolute value without removing the absolute value signs

Answer 16

The problem is then to evaluate
1-12-(-3)

Answer 17

when u solve this, 1-12-(-3), you move left to right, correct?

Answer 18

it doesn't matter. addition and subtraction can occur in any order

Answer 19

but isn't -8 not in absolute value because there was brackets around the equation not absolute value signs..

Answer 20

ahhhhh, i didn't notice that, i thought they were absolute value signs

Answer 21

so how do we go from there?

Answer 22

\[[1−12−(−3)]−|−15−18|=−8−|−33|\]

Answer 23

evaluate that stuff inside the absolute value sign

Answer 24

it makes it positive... so I do -8 + 33?

Answer 25

yup

Answer 26

the answer is -41 in the answer key tho

Answer 27

3.) 16a cubed -4a squared + 64a + 36 all over 4
\[\frac{16a^3-4a^2+64a+36}{4}\]

Answer 28

hmmmm....did you double check the problem, i don't see where we went wrong

Answer 29

i got it now
-8-|-33|=-8-(33)=-41

Answer 30

wait y do u do -(33)

Answer 31

oh because its positive?

Answer 32

because there are two negative signs near the number 33

Answer 33

we have
-|-33|
The absolute value signs only get rid of the negative inside of them

Answer 34

|-33|=33

Answer 35

oh ok... now can we do the other problem?(:

Answer 36

juantweaver?

Answer 37

Can u help me with it? Your a very good helper

Answer 38

yeah, got disconnected for a sec

Answer 39

\[\frac{16a^3−4a^2+64a+36}{4}\]

Answer 40

Is this the right problem