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A plane landing on a small tropical island has just 63 m of runway on which to stop.If its initial speed is 61 m/s, what is the maximum acceleration of the plane during landing, assuming it to be constant? and please explain
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you can use the equation : \(v^2-u^2 = 2as\)
thanks really helped
yw !! did you get a = 61^2 / 2*63 ?
yeah i did and another question how long does it take for the plane to stop with that acceleration? do i use a diffrent formula or ...
hmm don't forget "a" should be negative since plane is decelerating for time, use velocity equation v(t) = at + 61 ....set v=0 and solve for t
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ok thank i got -2.065573770488029
thats right, no -ve sign for time... its +2.0655
yeah thanks
np.. :D
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