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Chemistry 13 Online
OpenStudy (anonymous):

Indicate the concentration of each ion present in the solution formed by mixing 2.38 g of NaCl in 50.0 mL of 0.400 M CaCl2 solution.

OpenStudy (anonymous):

well first here is would covert 2.38g sodium chloride into moles....can you do this?

OpenStudy (anonymous):

yes. 2.38g/58.44g=4.07*10^-2 moles

OpenStudy (anonymous):

nice....now since we have .05L of .4M CaCl2 then how many moles of CaCl2 do we have?

OpenStudy (anonymous):

.02 moles?

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