If log(17) + log(y) = log(z), then 17 + y = z.
true or false? i thought z would be 17*y
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OpenStudy (anonymous):
since its addition it goes with multiplication
OpenStudy (anonymous):
Yes you think right..
OpenStudy (anonymous):
so the answer would be false
OpenStudy (anonymous):
\[\log(a) + \log(b) = \log(ab)\]
OpenStudy (anonymous):
what about: If ln(17x) = ln (y), then 17x = y.
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OpenStudy (anonymous):
Yes it will be false..
17y = z..
OpenStudy (anonymous):
Yes you are right again..
OpenStudy (anonymous):
so this is false too?
OpenStudy (anonymous):
How??
\(log(a) = log(b) \implies a = b\)
OpenStudy (anonymous):
\[\log(a) = \log(b) \rightarrow a = b\]
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OpenStudy (anonymous):
ah i gotcha!
OpenStudy (anonymous):
So is it false or true ??
OpenStudy (anonymous):
True
OpenStudy (anonymous):
Yes you are also true..
OpenStudy (anonymous):
Which of the following is equivalent to ln(3e^6)?
18
ln(3) + 6
36
6ln(3)
3e^6
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OpenStudy (anonymous):
Firstly use :
\[\log(ab) = \log(a) + \log(b)\]
OpenStudy (anonymous):
a = 3 and b = \(e^6\) here..
OpenStudy (anonymous):
dude your so helpful, i guess i just get confused when they throw an e in there but if u just look at the basic properties u can tell what to do with most of these
OpenStudy (anonymous):
(log(x))^7 = 7log(x)
so this would be true, am i correct?
OpenStudy (anonymous):
Yes it is correct but :
You should remember this :
\[\ln(e) = 1\]
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