Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

it is not easy to find the roots of a 5th degree polynomial, there is no formula for it. but you can make some guesses, because if it has a rational root they must be divisors of 12

OpenStudy (anonymous):

there are 4 real and positive roots

OpenStudy (anonymous):

1,2,3,4,6 and 12.?

OpenStudy (anonymous):

just do..hit and trail method...

OpenStudy (anonymous):

in fact \(-1\) is a root, and \(2\) is a root with multiplicity 2

OpenStudy (anonymous):

yes, those, and their negatives, so also \(-1,-2,-3,-4,-6,-12\) are possible

OpenStudy (anonymous):

1 does not work, the next good guess is to try -1, which does work i would use a graphing calculator, or better yet wolfram http://www.wolframalpha.com/input/?i=x%5E5+-+3x%5E4+%2B+3x%5E3+-+5x%5E2+%2B+12+%3D+0++

OpenStudy (anonymous):

ok so far i have : -1,2,2

OpenStudy (anonymous):

there are 4 real positive and 4 real negative roots

OpenStudy (anonymous):

what are they?

OpenStudy (anonymous):

in numerical terms ?

OpenStudy (anonymous):

just do..hit and trail method...

OpenStudy (anonymous):

Subs some valkues...for x and see whether u r getting 0

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!