.
it is not easy to find the roots of a 5th degree polynomial, there is no formula for it. but you can make some guesses, because if it has a rational root they must be divisors of 12
there are 4 real and positive roots
1,2,3,4,6 and 12.?
just do..hit and trail method...
in fact \(-1\) is a root, and \(2\) is a root with multiplicity 2
yes, those, and their negatives, so also \(-1,-2,-3,-4,-6,-12\) are possible
1 does not work, the next good guess is to try -1, which does work i would use a graphing calculator, or better yet wolfram http://www.wolframalpha.com/input/?i=x%5E5+-+3x%5E4+%2B+3x%5E3+-+5x%5E2+%2B+12+%3D+0++
ok so far i have : -1,2,2
there are 4 real positive and 4 real negative roots
what are they?
in numerical terms ?
just do..hit and trail method...
Subs some valkues...for x and see whether u r getting 0
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