A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below. What is the total volume of grains that can be stored in the silo? 44π ft3 24π ft3 52π ft3 176π ft3
Volume of cone+Volume of cylinder
\[{1 \over 3} \pi{r}^2h+\pi{r^2}h\]
to find the height of the cone, you take 13-10=3ft.
4 is the diameter. diameter=2radius 4/2=2ft is your radius.
i thought volume of a cone is 1/3 pi radius squared times height
now, plug in h1=3, h2=10 (height of cone) and r=2 into this equation. \[{1 \over 3} \pi{r^2}h1+\pi{r^2}h2\]
It is the same thing. when you multiply h into the equation, they can stand side by side. In this case, \[{1 \over 3}\pi{r^2} \times h={1 \over 3} \pi{r^2}h\]
i got 44 pi !
thanks :)
Yup! :) You're welcome!
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