Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to 5 decimal places):
x = -2.9,\; -2.99,\; -2.999,\; -2.9999, \; -3.1, \; -3.01,\; -3.001, \;-3.0001
If the limit does not exists enter DNE.

\lim_{ x \rightarrow -3 } \frac { 2 x + 6 } {x^2 - 4 x - 21}

Question

Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to 5 decimal places): 
x = -2.9,\; -2.99,\; -2.999,\; -2.9999, \; -3.1, \; -3.01,\; -3.001, \;-3.0001 
 If the limit does not exists enter DNE. 

\lim_{ x \rightarrow -3 } \frac { 2 x + 6 } {x^2 - 4 x - 21}

anonymous · Answer

$$\lim_{ x \rightarrow -3 } \frac { 2 x + 6 } {x^2 - 4 x - 21}$$

anonymous · Answer

First of all - factor the denominator and ACTUALLY DIVIDE the denumerat. by the denominat

anonymous · Answer

Hint Factoring is done by finding the solutions and plugging the negatives into monomial factors

anonymous · Answer

Got it ?

anonymous · Answer

yeah its -1/5