Question

Choose the correct simplification of the expression the quantity 4 times x all over y all to the second power.

4 times x to the second power all over y to the second power

8 times x to the second power all over y to the second power

16 times x to the second power all over y to the second power

16 times x to the second power all over y

Answer 1

hint: \[\huge \left(\frac{4x}y \right)^2 \implies \frac{(4x)^2}{y^2}\]
does that help?

Answer 2

is that the answer?

Answer 3

@dpaInc plzz help!!!!!!!!

Answer 4

all you need to do now is simplify what mr. lgbassallote did...
can you simplify \(\large (4x)^2 = \) ???

Answer 5

how do i do that

Answer 6

what does \(\large (something)^2 \) mean?

Answer 7

idk

Answer 8

what does \(\large a^2 \) mean ?

Answer 9

yes

Answer 10

????

Answer 11

how do i simplify 4x sq.

Answer 12

\(\large a^2 \) means \(\large a \cdot a \)
\(\large (something)^2 \) means \(\large (something) \cdot (something) \)
so
\(\large (4x)^2 \) means \(\large (4x)\cdot (4x) \)

Answer 13

so the answer is D.

Answer 14

no

Answer 15

:( ok

Answer 16

then.....

Answer 17

so the answer has to be C.

Answer 18

\(\huge \frac{(4x)^2}{y^2}=\frac{(4x)\cdot (4x)}{y^2}=\frac{4\cdot x \cdot4 \cdot x}{y^2} =\) ?????

Answer 19

do you understand why it's C?

Answer 20

yes i do thanks