Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

I need help with the attached problem please.

OpenStudy (anonymous):

hartnn (hartnn):

lets begin with 13-4x<16 subtract 13 from both sides

OpenStudy (anonymous):

You get: -4x<3

hartnn (hartnn):

good,now divide by -4 remember to flip the sign,as u are dividing by a negative number so < becomes >

OpenStudy (anonymous):

You get: x>-3/4

hartnn (hartnn):

thats your 1st part 13-4x>= -10 again subtract 13 from both sides

OpenStudy (anonymous):

You get: -4x>-23

hartnn (hartnn):

ok,don't forget = sign also now divide by -4 and flip sign

OpenStudy (anonymous):

You get: x< = 23/4

hartnn (hartnn):

now can u put the two thing together in interval notation ?

OpenStudy (anonymous):

Like this: First Part: X >-3/4 Second Part: x< = 23/4 Interval Notation: -3/4 < x < 23/4

hartnn (hartnn):

let me give example: 2<=x<6 [2,6)

OpenStudy (anonymous):

So... is it: [-3/4, 23/4) ?

hartnn (hartnn):

so, -3/4<x<=23/4 will give u (-3/4,23/4]

hartnn (hartnn):

as = part is with 23/4,u have ] bracket with 23/4

hartnn (hartnn):

got that?

OpenStudy (anonymous):

Okay I got it. I put the bracket for -3/4 before. That's where I went wrong.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!