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Mathematics 11 Online
OpenStudy (anonymous):

Determine whether the graph of y = x2 + 2x - 8 has a maximum or minimum point, then find the maximum or minimum value

hartnn (hartnn):

have u been taught the concept of derivatives ?

OpenStudy (anonymous):

no

hartnn (hartnn):

then can u plot y= x2 + 2x - 8 ?

OpenStudy (anonymous):

i can not

hartnn (hartnn):

then this question belongs to which topic? calculus?

OpenStudy (anonymous):

algebra

hartnn (hartnn):

then i can't help,sorry.........i will let @lgbasallote continue....

OpenStudy (lgbasallote):

sorry...can't help...i hate math too

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

start by factoring

OpenStudy (anonymous):

the right side of the equation

OpenStudy (anonymous):

then graph the two zeros that you find

OpenStudy (anonymous):

i don't know anything

OpenStudy (anonymous):

do you know how to factor a trinomial?

OpenStudy (anonymous):

if not use the quadratic equation \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

OpenStudy (anonymous):

where a, b, and c are found in the trinomial when the trinomial is in the following form: \[a*x^2+b*x+c\]

OpenStudy (anonymous):

The quadratic equation will give you the zeros of this polynomial

OpenStudy (anonymous):

Well, this one here is pretty easy. It's quadratic, so it's a parabola. Is the quadratic term negative or positive? (the x^2 term)

OpenStudy (anonymous):

The quadratic term is positive (+1), so the graph opens up. It will have a minimum and the maximum will be unbounded. (Will go on forever). The minimum will be the vertex. The x-value of the vertex can be found via -b/2a. Plug the result of that back into the original equation to get the corresponding y-value. That will be your minima.

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