find the limit of x approaches 0 (x/2-sin2(x)/4 why does this limit exist/ whydoes this limit not exist

Question

anonymous · Answer

$$\lim_{x \rightarrow 0} \frac{ x }{ 2 - \sin^2x} / 4$$

anonymous · Answer

??

anonymous · Answer

First thing you can do is plug this into your calc and take a look at the graph as it approaches 0 from both sides of zero

anonymous · Answer

I'm simply curious as to what this function actually IS. This is very ambiguous.

anonymous · Answer

right it is, i dont think you'll be able to clearly say "oh its looks like this or a parabola" it has a sin^2. so the top part you know is going to be going through a cycle you can solve a few chosen points..id choose 1, .01 and -1 and see what happens to my results. because sin is there Im thinking its going to turn into a wave of some kind. Drop a zero in for X you get 0/4 so you know its going to zero

anonymous · Answer

Well it will definitely be sinusoidal, just saying we can't really take a limit here because the way he wrote the function is incredibly ambigious. Hey @lomax111 would you mind drawing it?

anonymous · Answer

are you a taking Calc 1>?

anonymous · Answer

lim looks like it goes to zero.

anonymous · Answer

Depends on what the function really is. Can't answer accurately without response from OP.

anonymous · Answer

ok, Because sin is ^2 as you get to x values like .0001 or -.00001 the sign become irrelevant it gets so small it become negligible and goes to zero.