Question

dimensional analysis: d = 1/2 vi *t + a*t

Answer 1

Using SI unites:
d = distance (meters or m)
vi = velocity (meters/second or m/s)
t = time (seconds or s)
a = acceleration (meters/second^2 or m/s^2)
\[d = \frac{1}{2}V_i *t + a*t \]\[m=\frac{1}{2}\frac{m}{\cancel s}(\cancel s)+\frac{m}{\cancel {s^2}s}(\cancel s)\]
The dimensional analysis above shows that the result should be in meters...which is correct.

Answer 2

what about vf^2 = 2ad? I got m/s = 2kg/s^2m

Answer 3

I actually don't think I showed the cancellation correctly above when I did all the latex formatting but it does actually work out.

Anyway, the formula you posted should be:\[V_f^2-Vi^2=2ad\]\[(\frac{m}{s})^2-(\frac{m}{s})^2=\frac{m}{s^2}m=\frac{m^2}{s^2}=(\frac{m}{s})^2\]

Answer 4

no, it says vf^2 = 2 ad. but i think it's missing an initial velocity anyways.

Answer 5

I guess if Vi=0 then it would be correct to simplify it that way

Answer 6

yea... i think i'm just going to keep it that way lol. not my mistake. but that is true if vi = 0.

Answer 7

d - vi*t + a*t; i have m = m/1 + m/s. is that correct?

Answer 8

It looks like you're missing and "=" sign there...

Answer 9

*an

Answer 10

You need t^2 for the units to work out correctly:
d = v1t +at^2
m = m/s (s) + m/s^2 (s^2)

Answer 11

That too :)