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You need to use this identity for exponentials. \[10^{\log_{10}A}=A\]
From the graph y=10^x we end up with two points for the linear line.
point 1 : (0, 10^0) = (0, 1)
point 2: \[(\log 8, 10^{\log 8})\]
it looks like you were on the right track. At this point use the identity from above to simplify the y term of the 2nd point. ONce you do that you simply use the slope equation to find the slope
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First of all the line l is passing through the point (0,1).. and (log 8, 8).. now use the double-point formula to get the equation.. as |dw:1346389578262:dw|
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