Question

PLEASE HELP ME!!!!!!!!!!!!!!!!!!
Find the equation of the line l in the figure below. Let A = 3. Give exact values using the form y = mx + b.
m=?
b=?
http://www.webassign.net/hgmcalc/1-4-36fig_alt.gif

Answer 1

@ash2326

Answer 2

Given that the line l passes through two points
first point is where the curve f(x)=10^x cuts y axis
Second point is where x=log A in 10^ x (A=3)
could you tell me the coordinates of the first point?

Answer 3

would it be 10^x/2

Answer 4

it's where the line crosses y -axis

Answer 5

(0,6.27)

Answer 6

you are right, x coordinate is 0
\[f(x)=10^{x}\]
what's the value of f(x) for x=0?

Answer 7

1?

Answer 8

(0,1)

Answer 9

yeah, now we need to find the second point
it's given that x coordinate is log A, A=3 so log 3
find f(x) value for x = log 3
\[f(x)=10^x\]
put x= log 3, what would you get?

Answer 10

log3=1.0986
10^log3=12.549
which one do i use?

Answer 11

10 ^ log 3= 3 !!

Answer 12

sorry i was using ln!

Answer 13

(3,?)

Answer 14

(log 3, 3)

Answer 15

okay now whats next?

Answer 16

we have two points (0, 1) and (log 3, 3)
so equation of line L is
\[\frac{y-y2}{x-x2}=\frac{y1-y2}{x1-x2}\]
here (x2, y2)= (0, 1) and (x1, y1)=(log 3, 3)
it's just simplification, could you do this?

Answer 17

4.1918

Answer 18

you have to find the equation!!

Answer 19

how?

Answer 20

\[\frac{y-1}{x-0}=\frac{3-1}{\log 3-0}\]
cross multiply and simplify
you'll get the form y=mx+c

Answer 21

y=3x-x

Answer 22

you sure of this?? check again