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5i/6-2i simplify the expression
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multiply by the conjugate
ok then
plz show na
\[\frac{ 5i }{ 6-2i }\left( \frac{ 6+2i }{ 6+2i } \right)\]
ok is the solution sir
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no thats not the solution yet multiply it out
ok sir plz show na
\[\frac{ 30i+10i^2 }{ 36-4i^2 }\]
that turns into: \[\frac{ 30i+10(-1) }{ 36-4(-1) }\]
thanks for the solution n help sir
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well what did you get for your final answer
67/18+30i
sir m i correct
\[\frac{ 30i-10 }{ 40 }\]
rewrite it as: \[\frac{ -10 }{ 40 }+\frac{ 30i }{ 40 }\]
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ok
it reduces to: \[-\frac{ 1 }{ 4 }+\frac{ 3i }{ 4 }\]
^thats your final answer in a+bi form
thanks a lot i got it
np
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y
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