find the inverse function f(x)= 4-x over 2x+3
y = (4-x)/(2x+3) we want to solve for x y(2x+3) = 4-x 2xy+3y = 4-x 2xy+x = 4-3y x(2y+1) = 4-3y x = (4-3y)/(2y+1) now switch the x and y y = (4-3x)/(2x+1)
so the inverse is f^(-1)(x) = (4-3x)/(2x+1)
make sense?
@glares25 ? i see you bumped the question but i have answered it for you. is there anything you dont understand?
no i think your right , i just confused with my own answer thank you so much
let me know if anythng does not make sense. or yif you want to show me what you did we can see whats going on there.
thank you, my answer is -4 - x / 2x-3 but i think its nonsense
can you show me the steps you took to get there?
it seems to close to be nonsense prob a small error.
will you explain me x(2y+1) = 4-3y, i dont know how u get the 1 there. thank you
ok the line before that was 2xy+x = 4-3y so I factored out an x on the left hand side and get x(2y+1) = 4-3y
a(b+c) = ab+ac
ahhh ok thank you
np
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