Question

A 2.2-kg object is suspended from a spring with k = 18 N/m. The mass is pulled 0.35 m downward from its equilibrium position and allowed to oscillate. What is the maximum kinetic energy of the object

Answer 1

KE=\[\frac{ 1 }{ 2 }kx ^{2}\]

Answer 2

K=18 x=0.35

Answer 3

Because
ME=KE + GPE
max KE when GPE =0
\[ME=\frac{ 1 }{ 2 }kx ^{2} +mgh\]
but mgh=0
so,
\[ME=KE=\frac{ 1 }{ 2 }kx ^{2}\]