1/sinx

Question

1/sinx

zzr0ck3r · Answer

?

anonymous · Answer

how to solve it?

zzr0ck3r · Answer

u cant solve without = something

zzr0ck3r · Answer

this is sort of like saying solve 1/x

anonymous · Answer

i am suppose to complete that trig identity.

zzr0ck3r · Answer

1/sin(x) = csc(x)

zzr0ck3r · Answer

this is just notation though.... they are the exact same thing.

anonymous · Answer

ok and hw to complete this one- tan^2 x-1?

zzr0ck3r · Answer

devide every term of cos^2(x) + sin^2(x) = 1 with cos^2(x) and you get
1+ tan^2(x) = sec^2(x)       so 
-tan^2(x) -1 = -sec^2(x)

anonymous · Answer

there's no negative sign before tan (it was just a dash)

zzr0ck3r · Answer

hmm.

zzr0ck3r · Answer

you sure its not +1?

anonymous · Answer

no i mean the question is tan^2 x-1

anonymous · Answer

use brackets to be clear. is it tan^2(x-1)   ?

zzr0ck3r · Answer

do you know this identity

cos(2x) = cos^2(x) - sin^2(x)

thus

sin^2(x) -cos^2(x) = -cos(2x)

zzr0ck3r · Answer

are you saying 

tan^2(x) -1 

or

tan^2(x-1)?

anonymous · Answer

tan^2(x)-1

zzr0ck3r · Answer

sin^2(x) + cos^2(x) = 1     devide all terms by cos^2(x)
tan^2(x) + 1 = sec^2(x)      so
tan^2(x) = sec^2(x) - 1    thus
tan^2(x) - 1 = (sec^2(x) -1)-1 = sec^2(x) - 2
I think this is the best its going to get.

zzr0ck3r · Answer

does this make sense @taranidhi ?