Question

1/sinx

Answer 1

?

Answer 2

how to solve it?

Answer 3

u cant solve without = something

Answer 4

this is sort of like saying solve 1/x

Answer 5

i am suppose to complete that trig identity.

Answer 6

1/sin(x) = csc(x)

Answer 7

this is just notation though.... they are the exact same thing.

Answer 8

ok and hw to complete this one- tan^2 x-1?

Answer 9

devide every term of cos^2(x) + sin^2(x) = 1 with cos^2(x) and you get
1+ tan^2(x) = sec^2(x) so
-tan^2(x) -1 = -sec^2(x)

Answer 10

there's no negative sign before tan (it was just a dash)

Answer 11

hmm.

Answer 12

you sure its not +1?

Answer 13

no i mean the question is tan^2 x-1

Answer 14

use brackets to be clear. is it tan^2(x-1) ?

Answer 15

do you know this identity

cos(2x) = cos^2(x) - sin^2(x)

thus

sin^2(x) -cos^2(x) = -cos(2x)

Answer 16

are you saying

tan^2(x) -1

or

tan^2(x-1)?

Answer 17

tan^2(x)-1

Answer 18

sin^2(x) + cos^2(x) = 1 devide all terms by cos^2(x)
tan^2(x) + 1 = sec^2(x) so
tan^2(x) = sec^2(x) - 1 thus
tan^2(x) - 1 = (sec^2(x) -1)-1 = sec^2(x) - 2
I think this is the best its going to get.

Answer 19

does this make sense @taranidhi ?