Question

how the heck do you simplify (3/16x^3)^(1/5)???

Answer 1

you're not clear enough its a bit ambiguous. do you want:

\[(\frac{3}{16x^3})^{\frac{1}{5}} \text{ or } (\frac{3}{16}x^3)^{\frac{1}{5}}\]

Answer 2

the first one!

Answer 3

well, as far as i can see there's not much you can do there to be honest

Answer 4

man really? the answer is the fifth root of 6x2 all over 2x

Answer 5

i mean 6x^2

Answer 6

\[\sqrt[5]{\frac{ 3 }{ 16x^3 }}\] i dont really see anything else to do

Answer 7

dude nickhouraney that's the original problem

Answer 8

im aware lol

Answer 9

hmm hold on a sec

Answer 10

the answer \[\frac{\sqrt[5]{6x^2}}{2x}\]
is equal to what we started with, i dont know whether i'd call it simpler.. hmm maybe

Answer 11

i suppose the powers are a bit nicer

Answer 12

thanks eigenschmeigen, but how did they get to that?

Answer 13

Some little arrangements we have to make..

Answer 14

can someone else explain? i have to go :(

Answer 15

Multiply and divide by 2 and \(x^2\)..

Answer 16

\[\large (\frac{3 \times 2 x^2}{16x^3 \times 2 x^2})^{\frac{1}{5}} \implies (\frac{6x^2}{2^5x^5})^{\frac{1}{5}}\]

Answer 17

Now denominator will simply be taken out of the 5th root brackets :

\[\large \frac{(6x^2)^{\frac{1}{5}}}{2x} \; \; Or \; \; \frac{\sqrt[5]{6x^2}}{2x}\]

Answer 18

\(16 \times 2 = 32 = 2^5\)

Answer 19

i'm just gonna fail this problem thanks for trying bro

Answer 20

What happened ??

Answer 21

Which step you are not getting ??

Answer 22

i just would never think of multiplying by the x^2

Answer 23

thanks though. i actually understand it kinda

Answer 24

Welcome..