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Mathematics 17 Online
OpenStudy (anonymous):

If heat is the random kinetic energy of jiggling particles, in what way is it different to temperature?

OpenStudy (ghazi):

temperature is degree of hotness and coldness whereas heat is energy in transit

OpenStudy (anonymous):

Temperature is THE AVERAGE INTENSITY OF MOTION of the molecules. But HEAT is THE OVERALL QUANTITY of Kinetic energy. Good question! Temperature is INTENSIVE while HEAT is accumulated- EXTENSIVE

OpenStudy (anonymous):

Given how we mention temperature, surely some of the jigglings cancel out vectorially also?

OpenStudy (anonymous):

Again: temperature is related (not actual \[E_{KIN}\] but a function of it} to the kinetic energy of a "typical" molecule. Like , say, average income of a US citizen/ While HEAT is the OVERALL SUM of ENRGIE-S - like the overall GDP of the country

OpenStudy (ghazi):

they do cancel out but temperature gives us an average

OpenStudy (anonymous):

Kinetic energy is a scalar, and positive one only !

OpenStudy (anonymous):

Yes, but for temperature

OpenStudy (anonymous):

Sorry ghazi - You mislead people. Kinetic ENRGIES DO NOT CANCEL EACH OTHER !

OpenStudy (anonymous):

The are NOT-vectors and , not cancel each other!

OpenStudy (ghazi):

i am not talking about kinetic energy and fyi please go through the dynamics of heat vectors

OpenStudy (anonymous):

I understood that before! But can opposite KEs reduce the temperature?

OpenStudy (anonymous):

Sorry man - henpen asked specifically about temperature, and it is A SCALAR. NO henpen -YOU HAVE BEEN MISLEAD (AS I expected) KE CANNOT CANCEL EACH OTHER

OpenStudy (anonymous):

KE only ADD and ACCUMULATE

OpenStudy (anonymous):

ANd HEat, my dear ghazi IS NEVER A VECTOR !!!!!! http://www.answerbag.com/q_view/509829

OpenStudy (ghazi):

talking about it at a molecular level heat is function of collision of molecules too kindly take that into consideration..i do agree KE is of course a scalar quantity but you can't ignore mean velocity factor that accounts for develope heat by the way thanks @Mikael

OpenStudy (anonymous):

No, you have been mislead into thinking that I have been mislead. |dw:1346413966312:dw| This is my question.

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