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Prove that : \[\huge \underset { x\quad \rightarrow 0 }{ \lim } \frac { \sin\quad x }{ x } =\quad 1\]
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@lgbasallote WELCOME
l'hospital's rule
@henpen welcome too
you can also use squeeze theorem
or you can use the tabular method
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EXPLAIN BOTH THE METHODS PLS
http://www.youtube.com/watch?v=Ve99biD1KtA Is a good explanation of the 1st one
@lgbasallote INCOMPLETE help
Okay then
The original equation is the definition of the derivative of sin(x) at 0. You know calculus, right?
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Okay
COME on Give a BETTER response
what can be better than that? the geometric argument is long and annoying it is \(\sin'(0)=\cos(0)=1\)
Thanks
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