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Mathematics 14 Online
OpenStudy (anonymous):

Prove that : \[\huge \underset { x\quad \rightarrow 0 }{ \lim } \frac { \sin\quad x }{ x } =\quad 1\]

OpenStudy (anonymous):

@lgbasallote WELCOME

OpenStudy (lgbasallote):

l'hospital's rule

OpenStudy (anonymous):

@henpen welcome too

OpenStudy (lgbasallote):

you can also use squeeze theorem

OpenStudy (lgbasallote):

or you can use the tabular method

OpenStudy (anonymous):

EXPLAIN BOTH THE METHODS PLS

OpenStudy (anonymous):

http://www.youtube.com/watch?v=Ve99biD1KtA Is a good explanation of the 1st one

OpenStudy (anonymous):

@lgbasallote INCOMPLETE help

OpenStudy (anonymous):

Okay then

OpenStudy (anonymous):

The original equation is the definition of the derivative of sin(x) at 0. You know calculus, right?

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

COME on Give a BETTER response

OpenStudy (anonymous):

what can be better than that? the geometric argument is long and annoying it is \(\sin'(0)=\cos(0)=1\)

OpenStudy (anonymous):

Thanks

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