Explain, in terms of particles, concentration, and reaction rate, what you expect to happen when methane gas (CH4) and hydrogen sulfide gas (H2S) are sealed in a flask and reach a state of equilibrium. CH4 (g) +2 H2S (g) CS2 (g) + 4 H2 (g)

Question

Explain, in terms of particles, concentration, and reaction rate, what you expect to happen when methane gas (CH4) and hydrogen sulfide gas (H2S) are sealed in a flask and reach a state of equilibrium. 

CH4 (g) +2 H2S (g) <-- -->  CS2 (g) + 4 H2 (g)

.sam. · Answer

You have 3 moles on the left and 5 moles total on the right, so to reach equilibrium, you have to lose CS2 and H2 in order to reach equilibrium, the reaction will shift towards left to give more reactants

anonymous · Answer

Is can you show me how i would set it up andsolve it?

.sam. · Answer

I don't think you need to solve anything here, they just want you to explain

anonymous · Answer

oh ok and thats would i would explain?  about losing the CS2 and H2?