Question

guys help me with this plz
1/a +1/b = 1/c
solve for b

Answer 1

what is your first step?

Answer 2

i believe moving a to c

Answer 3

i have the answer but i get in trouble on here for just giving answers out.

Answer 4

You can get rid of the denominators by multiplying each side by a*b*c

Answer 5

i got 1/b = 1/c - 1/a

Answer 6

then what should i do next ?

Answer 7

do what robtobey said

Answer 8

If a c + b c =a b were true, could you now solve for c?

Answer 9

idk :| im suck at math

Answer 10

so i've got bc+ac=ab

Answer 11

thats not right

Answer 12

\[\frac1a+\frac1b=\frac1c\]\[\cancel abc(\frac1{\cancel a})+a\cancel bc(\frac1{\cancel b})=ab\cancel c(\frac1{\cancel c})\]\[bc+ac=ab\]

Answer 13

now get all the terms that have b on the same side of the equals sign, then factor out the b

Answer 14

so the final answer is \[\frac{ ac }{a-c }\]

Answer 15

yeah looks good :)

Answer 16

tks :)