I am working on averaqe rate of change of a function and i need help simplifying this [sin 3pi/2 -sin5pi/6] / 3pi/2 -5pi/6
\[\Large{\sin(\frac{3\pi}2)-\sin(\frac{5\pi}2)\over\frac{3\pi}2-\frac{5\pi}2}\]
right?
yes
I would evaluate sine functions first.
wasn't that a 5pi/6?
oh yeah. i missed that. thanks
its 5pi/6
k... what do you get for sin(3pi/2) and sin(5pi/2)?
You can use unit circle, reference triangles, or even a calculator in radian mode.
the choice of ansers given were not completely simplified and thats whats confusing. When i use a calcultor, it simplifies it to 88.
Oh, I was just talking about the sines for the calculator.
but the choice of answers are all in fractions with pi in them
sin(3pi/2)=-1 What is sin(5pi/2)?
1
Yes, so you have -1-1 in the numerator... which simplifies to?
-2
Yes, now find the lowest common denominator of the fractions in the denominator.
Both 2 and 6 go into what number?
6
Yes, so change 3pi/2 into sixths by multiplying top and bottom by the number that makes 2 into 6...which is 3.
\[\frac{3}{3}\frac{3\pi}{2}=\frac{9\pi}{6}\]
9pi/6
ok
yes, now combine the fractions below by subtracting their numberators.
15pi/18
-6pi
\[\frac{9\pi}{6}-\frac{5\pi}{6}=\frac{4\pi}{6}\]
Here is what I have all together now.\[\frac{-2}{\frac{4\pi}{6}}\]
To divide fraction, invert the denominator and multiply by the numerator.\[-2(\frac{6}{4\pi})\]and reduce.
Any questions, or maybe a possible answer?
when you multipied the denom and numer of the first fraction by 3, why didnt you do it to the second fraction?
I was changing its form so that I could subtract the fractions. A common denominator is required to subtract fractions. By multiplying the same number top and bottom 3/3, it was like multiplying by one. It changes its form without changing its value.
ok i got it. because 9pi/6 is the same as 3pi/2
yes
and at that point it is compatable with 5pi/6... so we can subtract them.
ok. their final answer came out to be -9/4pi
bummer, that is not what I got... let me double check.
Oh I see... I missed that your original sine was 5pi/6 as well. I thought it was 5pi/2.
oh yeah, your right
sin(5pi/6)=1/2
-1-1/2 in the numerator gives -3/2
\[\frac{-\frac{3}{2}}\frac{4pi}{6}\]
editor is giving me problems... -3/2 in the numerator 4pi/6 in the denominator
Invert and multiply denominator...\[-\frac{3}{2}\frac{6}{4\pi}\]
Bummer, it still looks bad on my screen. But yes, in the end it comes down to -9/4pi.
yes it sure does . thanks a lot
No problem. It was fun until I started getting glitches.
lol. i know. its difficult typing those characters in
i got another similar problem
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