Question

The local zoo has two water tanks for the elephant exhibit that are leaking One water tank contains 12 gal of water and is leaking at a constant rate of 3 gal/h. The second water tank contains 8 gal of water and is leaking at a constant rate of 5 gal/h. When will the two tanks have the same amount of water? Explain. Let x = the number of hours the tanks are filling and let y = the number of gallons in the tank.

Answer 1

A. In 2 hours, because the solution to the system is (2,18).
B. They will never have the same amount of water because the solution to the system is (–2,18). It is not possible to have time be –2 hours.
C. In –2 hours, because the solution to the system is (–2,18).
D. They will never have the same amount of water because the solution to the system is (–2,18). It is not possible to have –2 gallons in the tanks.

Answer 2

i know it is not (D)

Answer 3

Do you know what the system of equations should be?

Answer 4

no

Answer 5

Look at the situation: The first tank starts at 12 and loses 3 each hour, so after x hours, it has 12-3x gallons left. Similarly for the second, after x hours, it has 8-5x gallons.
x represents the unknown time that it is asking for and the condition of "same amount of water" means you set the two equations equal to each other.

Answer 6

(A)

Answer 7

????

Answer 8

@.sam.

Answer 9

Why don't you just solve it yourself. I set up the equations for you, it's a two-step linear equation with one variable. I know you can handle that.