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Mathematics 20 Online
OpenStudy (anonymous):

9p^4+30p^3+25p^2

OpenStudy (anonymous):

does this need to be factor or find the roots of

OpenStudy (anonymous):

factor

OpenStudy (anonymous):

okay so what is a common factor with this one

OpenStudy (anonymous):

hint is is not a number but a variable

OpenStudy (anonymous):

Looks like a perfect square . . .

OpenStudy (anonymous):

p

OpenStudy (anonymous):

what are you trying to say

OpenStudy (anonymous):

you can do this more then one way p^2 is what I was looking for

OpenStudy (anonymous):

do you have choices or who just have to show your work

OpenStudy (anonymous):

just show work

OpenStudy (anonymous):

okay so now we have found the common factor as p^2 right

OpenStudy (anonymous):

yes..(9p^2+30p+25p)

OpenStudy (anonymous):

no p after 25

OpenStudy (anonymous):

and don't forget to put p^2 on the outside like this\[p^2 (9p^2 + 30p + 25)\]

OpenStudy (anonymous):

ok then what would i do

OpenStudy (anonymous):

that is the answer you had it but you just forgot the common factor that I had you come up with the p^2 and you put p on the end of 25 and it did not belong there do you see that now?

OpenStudy (anonymous):

yes thanks

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

*ahem* \[(ax+b)^2 = a^2x^2+2abx+b^2.\]

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