Please help!!!! Find the coordinates of the orthocenter for triangle ABC. (Diagram in comments)
It may seem simple to you, but I am clueless when it comes to geometry.
nope
Orthocenter is intersection of altitudes, right? It's been a while since I've done these . . .
Yeah
Eh.. I'm sure there's an easier way using some theorem I can't remember right now, so my first instinct is to set up a system of equations using distance formula.
It's isosceles, so that simplifies things . . .
Right
Here's what I'm seeing now from the picture for the purpose of simplifying assumptions: It's isosceles, so one altitude is going to go from B(6,6) to (6,0) because of symmetry. Also because of symmetry, the other two altitudes are going to be equal in length.
And, for example, the altitude going from A(0,0) to side BC has to be perpendicular to that side, so you know that line has opposite-reciprocal slope to the line which contains BC.
Can you find it from there?
My first instinct seems unnecessary - distance formula isn't required, only the system of two lines to find the intersection point.
In fact, I think ganeshie8 was right, it is a right triangle, so the solution is trivial.
Trivial...okay. I think
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