Question

An electron and a proton are each placed at rest in a uniform electric field of magnitude 554 N/C. Calculate the speed of each particle 51.6 ns after being released.

Answer 1

\[F=Eq=554*1.6*10^{-19}=ma=9.1*10^{-31}a\]

Answer 2

\[s=\frac{1}{2}at^2=\frac{554*1.6*10^{-19}}{2*9.1*10^{-31}}(51.6*10^{-9})^2\]

Answer 3

For a proton, replace 9.1*10^-31 with the proton's (kg) mass

Answer 4

Do you get this?

Answer 5

@riptidej ?

Answer 6

i dont

Answer 7

i'm sorry..i just never understood physics and i just dont get it

Answer 8

Fair enough. OK- the Electric field strength at a point is just the force exerted on a unit charge. Is that OK?

Answer 9

(btw I will NOT explain it as well as http://www.youtube.com/watch?v=OsWDUqJQcpk&feature=relmfu if you have the time)

Answer 10

ok

Answer 11

i will take a look

Answer 12

So E at a point is in the same direction as the force, but is the F/q: force divided by the charge on that object, as force in a way is useless in that you don't know how strong the electricity is unless you account for the strength of the charge it is moving

Answer 13

So E=F/q

F=E*q, which by Newton's 2nd law is also =ma

Answer 14

Stop me if you have any question!

Answer 15

ok
i see that in my book..that formular..but when i used it..i got the wrong answer. so i must have messed up the formula

Answer 16

So the acceleration (to do with velocity/ speed- what we are trying to find, so we're going to isolate it) is equal to
=a=Eq/m

Answer 17

Did you try plugging in the numbers above?

Answer 18

Sorry, my above formula gives the displacement, not the velocity.
It should be
\[v=at\]
So take away the 1/2 and the squared sign on the time

Answer 19

So:
Acceleration is how fast the thing speeds up per second, so its speed is acceleration*time
v=at

You know a=Eq/m
You know t

Substitute the actual values and work out V

Answer 20

google the electron/proton's mass, charge etc.

Answer 21

ok

Answer 22

For the electron it turns out as 886400

Answer 23

it says thats wrong

Answer 24

I made some approximations of the mass/charge of the electron. It obviously wants it more precise.

Answer 25

it says its off by 10%