Divide please: 2x^3-x^2y-11xy^2+10y^3 / x-2y

Question

compassionate · Answer

$$2x^3 - x^2y-11xy^2+10y^3 / x-2y$$

anonymous · Answer

that is correct

compassionate · Answer

Add like terms, can you do that?

anonymous · Answer

one sec

anonymous · Answer

trying to figure out how to do this

compassionate · Answer

$$2^3 + 10x^3$$ = ?

$$-x^2y-11xy^2$$= ?

anonymous · Answer

the first one is 12x^3?

anonymous · Answer

-12x1y1 for the second one?

compassionate · Answer

No, 

2^3 = 8, 

8 + 10x^3 = ?

anonymous · Answer

18x^3

compassionate · Answer

Eh, I'm trying to get the point across that you can't add any of these :)

anonymous · Answer

oh

compassionate · Answer

$$\frac{ 2x^3-x^2y-11xy^2+10y^3 }{ x-2y }$$

2x - x - 5.5y + 5y^2

anonymous · Answer

so that would be 1x-5.5y+5y^2

anonymous · Answer

?

compassionate · Answer

Technically x-2y cannot be solved further, so the original expression is also the final expression.

anonymous · Answer

the one you wrote right? and no remainer? so that's my answer

compassionate · Answer

Well, yes and no. I'm still not sure what form of division you're doing. I know three different methods and applications. Which form of division is this?

anonymous · Answer

the problem just says to divide

compassionate · Answer

That's not very good advice... It doesn't specify what type of division.

anonymous · Answer

nope it just says Divide.

anonymous · Answer

and then for the answer box it has quotient =

anonymous · Answer

you want either synthetic division or long division. have you done either of these before?

anonymous · Answer

It has to be long divison because it dosen't say synthetic

anonymous · Answer

will u look up to the answer on up and tell me if that's right?

anonymous · Answer

ill have a go.. i have to admit i haven't tried algebra division with 2 variables

anonymous · Answer

i did it :D i think it factorises:

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