Question

sin^−1(sin(4pi/3))=??

Answer 1

hint:
\[\huge \sin^{-1} (\sin x) = x\]
\[\huge \sin (\sin^{-1} x) = x\]

does that help?

Answer 2

nooo it doesnt equal x

it equals -pi/3

Answer 3

uhh you do realize what i wrote is different from what you wrote right?

Answer 4

i was stating the "general rule"

Answer 5

ok then it would be 4pi/3

Answer 6

keep in mind that the range of arcsine is [-pi/2, pi/2]

Answer 7

so -pi/3 is actually the answer

Answer 8

if you simplify 4pi/3 you get -pi/3

Answer 9

not quite, but sin(4pi/3) = sin(-pi/3)

Answer 10

\[\huge \sin^{-1} (\sin (\frac{4\pi}{3}) \implies \sin^{-1} (\sin (-\frac{\pi}{3}))\]
that'swhat i meant

Answer 11

then following the rule i said... that becomes -pi3

Answer 12

-pi/3*