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if A,B,C are interior angles of triangle ABC,show that cos^2 A/2+cos^2(B+C/2)=1 plss help me ma maths page is not available plsss help mee frnds....
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i will look at this. give me a second. And please verify this is the correct equation\[\cos^{2}(\frac{A}{2})+\cos^{2}(B+\frac{C}{2})=1\]
its\[\cos^{2}(\frac{A}{2})+\cos^{2}(\frac{B+C}{2})=1\]
yaaa
juantweaver go on
i am not sure what to do yet
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anyway plss show d method
\[A+B+C=\pi\]\[\frac{B+C}{2}=\frac{\pi}{2}-\frac{A}{2}\]so\[\cos(\frac{B+C}{2})=\cos(\frac{\pi}{2}-\frac{A}{2})=\sin (\frac{A}{2})\]
dis is too complicated i dnt wanna knw
np :)
thx for ur effort
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