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Solve Integral
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\[\int\limits_{}^{} \sec^2x cosec^2x dx\]
\[2\csc(2x) \implies \sec x \csc x\] right? so... \[\sec^2 x \csc ^2 x \implies 4\csc^2 (2x)\] so the integral becomes \[\int 4\csc^2 (2x) dx\] does that help?
rewrite the integrand\[\sec^2 x \csc ^2 x = \frac{1}{\cos^2 x \sin ^2 x}\]\[= \frac{1}{(\sin x \cos x)^2 }\]\[= \frac{1}{\left(\frac{1}{2}\sin 2x\right)^2}\]\[= 4 \csc^2 (2x)\]
and another one maybe this help :\[\sec^2 x \ \text{cosec}^2x=(1+\tan^2 x)(1+\cot^2 x)=1+\tan^2 x+(1+\tan^2 x)\cot^2 x\]
Oh ! Nice one there everybody.. I got into integration by parts LOL !!
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Thanx all
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