Mathematics
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OpenStudy (anonymous):
x/3+2x/15< less than with aline under it 2/3 what is the solution set
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OpenStudy (anonymous):
please help me
OpenStudy (anonymous):
Less than what?
OpenStudy (anonymous):
2/3
OpenStudy (anonymous):
\[\frac{x}{3}+\frac{2x}{15}<\frac{2}{3}\] Multiply both sides by 15 first
OpenStudy (anonymous):
This will also cancel the 3s in the denominator as 15 is a multiple of 3
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OpenStudy (anonymous):
yes but the symbol for less than has a line under it
OpenStudy (anonymous):
That means 'less than or equal to'. Treat it the same as a normal 'less than' algebraically.
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
\[< \rightarrow \le\]
OpenStudy (anonymous):
ok got ya so how would i get the solution set
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OpenStudy (anonymous):
Although obviously when you're computing possible answer take account that it could also be equal to the thing.
OpenStudy (anonymous):
Multiplying by 15:\[5x+2x \le 10\]
OpenStudy (anonymous):
Rearrange to make x the subject, and there is your answer.
OpenStudy (anonymous):
can you help me with that
OpenStudy (anonymous):
What is 5x+2x?
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OpenStudy (anonymous):
7x
OpenStudy (anonymous):
\[7x \le 10\]
OpenStudy (anonymous):
Divide by 7 to get 1x on the left.
OpenStudy (anonymous):
\[\frac{7x}{7}=x \le\frac{10}{7}\]
OpenStudy (anonymous):
So x is equal to any number smaller than or up to 10/7
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OpenStudy (anonymous):
so is the solution set x<10/7
OpenStudy (anonymous):
|dw:1346506628014:dw| Not the < sign , but with the 'or equal to' line under it, yes.