Question

A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^-28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?

Answer 1

Density = MASS/VOLUME

Answer 2

use it to find the volume of the sphere

Answer 3

I just set up the following relation 6x10^-28=100kg/V

Answer 4

Yes u r correct. PLZ CONTINUE

Answer 5

So, with some algebric manipulation i found this relation V=1x10^2/6x10^-28 and i got V=1/6x10^30.

Answer 6

I think this is the volume of the sphere.

Answer 7

Now, Volume of a sphere=4/3 pi r^3

Answer 8

Use it to find r

Answer 9

I just plug it in the formual, right?

Answer 10

YEp, 1/6x10^30 = 4/3 pi r^3

Answer 11

got it?

Answer 12

Just one moment.

Answer 13

i got 1,46459

Answer 14

But I got different

Answer 15

What do you got?

Answer 16

i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r

Answer 17

Now i got 4,12740906x10^9 m

Answer 18

Density= MASS/ VOLUME
2x10^-28=100/VOLUME
VOLUME=50 * 10 ^28
4/3 pi r^3 = 50 * 10^28
r^3=4923725109

Answer 19

That ´s right.

Answer 20

r=4923725109

Answer 21

How do u calculate the 2x10^-28=100/VOLUME. Plz do it step by step.

Answer 22

DEnsity =MASS/ VOLUME

Answer 23

Now, substitute the given values

Answer 24

thanks

Answer 25

:)yw

Answer 26

But sorry i can´t understant how do you calculate 2x10^-28=100/VOLUME. May you do it plz?

Answer 27

When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.

Answer 28

100/2 =50 right?

Answer 29

Yes, but where did you find the number two? If we have the division 100/6?

Answer 30

Did you divide 6/3. I got it. now.