How to calculate the sum : 1/sqrt(10000) + 1/sqrt(10001) + 1/sqrt(10002) ... + 1/sqrt(1000000)
\[\Large\sum_{i=10^4}^{10^6}\frac1{\sqrt i}\]???
yea, like that...
maybe they mean to find floor of this !!
but no said to find floor of this question..
http://www.wolframalpha.com/input/?i=sum++1%2Fsqrt%28n%29++from+10%5E4+to+10%5E6
hmmm... but i want to know using algebraic to solve it give me idea mukushla
yeah this problem wants the floor... http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_medium;action=print;num=1136228390
integral part means floor
ohhh... i just know that "integral part means floor" but i dont look its integral process??
actually \[{1\over\sqrt{k+1} + \sqrt{k}} < {1\over 2\sqrt{k}} < {1\over\sqrt{k-1} + \sqrt{k}}\]
rationalize the denum for LHS and RHS of inequality u have\[\sqrt{k+1} - \sqrt{k} < {1\over 2\sqrt{k}} <\sqrt{k} - \sqrt{k-1}\]
apply the sigma
Ok i got it... i think this problem can be solved with integral or simplify one by one that fractions lol... thanks mukushla
very welcome
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