a stone is dropped from a height of 100m on earth .at the same time another stone is thrown vertically upwards from a groung with velocity of 50m/s at what height from the ground will the stone meat?

Question

anonymous · Answer

whr r u stuck

3psilon · Answer

Since the X finals have to be equal we will use $$X{f} = X{i} + V{i} t + 1/2(a) t^{2}$$ for both our formulas

3psilon · Answer

For our first formula $$X{i} = 100 m$$ and Acceleration due to gravity is -9.8 so that is our Acceleration. So the first formula looks like this
$$X{f} = 100m + 1/2(-9.8m/s^{2})$$

For formula number 2 We have $$V{i} = 50 m/s$$ and $$a = -9.8 m/s^{2}$$ So formula number two looks like $$X{f} = 50m/s(t) + 1/2(-9.8) t^{2}$$ Now in order to find the distance at where they meet we need the time at which they meet. So set the equations equal to each other and solve for time. $$100m  + (1/2)(-9.8m/s^{2})t^{2} = (50m/s)t + (1/2)(-9.8m/s^{2})t^{2}$$
So just solve for the time which should equal 2 seconds and plug it into either equation 1 or equation 2 , And you should get 80.4m as where they meet

3psilon · Answer

Let me know if you get it @tahoor