Question

anyone know about oblique asymptote??

Answer 1

http://en.wikipedia.org/wiki/Asymptote#Oblique_asymptotes

Most asymptotes are in the form of x=c or y=k (i.e. parallel to the y/x-axis), but oblique ones are those that do not have this property.

Answer 2

would you mind taking a look at a problem?

Answer 3

Fine

Answer 4

says i need to find the oblique asymptote if it exists

Answer 5

oblique asymptotes occur on RATIONAL function when the degree of the numerator is 1 more than the degree of the denominator...

Answer 6

to get the equation of the asymptote, just do long division and forget about the remainder.

Answer 7

Sorry- you cant divide by 0, so x=4 will be an asymptote.

Answer 8

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIoeF4yLTEyeC0xKS8oeC00KSIsImNvbG9yIjoiIzAwMDAwMCJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi05NC4wNjEyNDA1NTM4NTU1OCIsIjk1LjExMzY1NzQxNDkxMjg2IiwiLTYyLjQwMDQ2Mzk2ODUxNTI0IiwiNTQuMDE0ODU3ODU4NDE5MjYiXX1d

Answer 9

Does [degree of the numerator is 1 more than the degree of the denominator] guarantee that there will be an asymptote?

Answer 10

\(\large f(x)=\frac{x^2-12x-1}{x-4} \) did you want vertical or oblique asymptotes? this function has both.

Answer 11

i believe the final answer would be y=x +8 ??

Answer 12

yes.... the degree guarantees it, as long as the rational function is REDUCED to simplest terms...

Answer 13

that is, common factors are cancelled from the numerator and denominator.

Answer 14

ok nice

Answer 15

Sorry to butt in, but what is the function linking the eqn. of the oblique asymptote with the original function?

Answer 16

@henpen, could u restate your question? i don't understand it....

Answer 17

do you mean what is the equation of the oblique asymptote?

Answer 18

\[\frac{x^2-12x-1}{x-4}\rightarrow x+8\] What is\[\rightarrow \]?

Answer 19

Is there a function, g(f(x)), that maps f(x) to its oblique asymptote's equation, h(x)?

Answer 20

idk about a function h(x) that maps of f(x) to the asymptote, but all i do know is to get the equation of the oblique asymptote, you just have to perform long division.... at least that's how i've done it..... sorry....

Answer 21

Long divide what? x^2-12x-1 by x-4?

Answer 22

yes.....

Answer 23

To get x+8? I wonder why that works? Thanks!