write the sum or difference in the
standard form a +bi

(squareroot sign 5 -3i) + (-2+ squareroot sign-9)

Question

write the sum or difference in the 
standard form a +bi

(squareroot sign 5  -3i) + (-2+ squareroot sign-9)

shivaniits · Answer

what's ur equation..??
is it$$(\sqrt{5}-3i)+(-2+\sqrt{-9})..??$$

anonymous · Answer

$$(\sqrt{5} - 3i) + (-2 + \sqrt{-9}) \implies (\sqrt{5} -2) + (-3i + \sqrt{-9})$$

anonymous · Answer

Remember :

$$\sqrt{-9} = i \sqrt{9} = 3i$$

anonymous · Answer

So:

$$(\sqrt{5} -2) + (-3i + 3i) = ??$$

shivaniits · Answer

i think then $$\sqrt{-9}$$-3i could be written as 0i as $$\sqrt{-9}$$=3i and answer would be only real no $$\sqrt{5}-2$$

anonymous · Answer

@uri, your girl child is looking very cute in the pic..

ha ha ha..

uri · Answer

thats a baby boy.

anonymous · Answer

thanks guys! that helped a lot!

anonymous · Answer

Oh you have two kids ??

Ha ha ha..

anonymous · Answer

@sparki1 you are welcome..