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Mathematics 10 Online
OpenStudy (anonymous):

factor out the greatest common factor. 2x^2y+6x^2y^2-16xy

jimthompson5910 (jim_thompson5910):

What's the GCF

OpenStudy (anonymous):

Greatest common factor

jimthompson5910 (jim_thompson5910):

Yes, but what is it in this case

OpenStudy (anonymous):

I'm not sure.

jimthompson5910 (jim_thompson5910):

What's the GCF of 2, 6, -16 ?

OpenStudy (anonymous):

like what number will go into these?

jimthompson5910 (jim_thompson5910):

yes, the largest number in all 3

OpenStudy (anonymous):

t would be 6 right

jimthompson5910 (jim_thompson5910):

6 is a factor of 2?

jimthompson5910 (jim_thompson5910):

and 6 is a factor of 16?

OpenStudy (anonymous):

yea

jimthompson5910 (jim_thompson5910):

no, 6 is not a factor of 16

OpenStudy (anonymous):

oh yea

OpenStudy (anonymous):

ok so what would i do from here?

jimthompson5910 (jim_thompson5910):

keep looking for that GCF and tell me what else you get

OpenStudy (anonymous):

2 is a factor of 16

jimthompson5910 (jim_thompson5910):

good, and it's also a factor of 6

jimthompson5910 (jim_thompson5910):

and it turns out that 2 is the GCF of 2, 6, and -16

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

now find the GCF of the variable terms

OpenStudy (anonymous):

it would be 2 right ?

jimthompson5910 (jim_thompson5910):

that's the GCF of the coefficients

jimthompson5910 (jim_thompson5910):

what about the variable terms

OpenStudy (anonymous):

it's x and y right

jimthompson5910 (jim_thompson5910):

x^2y, x^2y^2, xy

jimthompson5910 (jim_thompson5910):

close, it's actually xy

jimthompson5910 (jim_thompson5910):

So combine these two GCFs to get the final GCF to be 2xy

jimthompson5910 (jim_thompson5910):

Now factor out the GCF 2xy

OpenStudy (anonymous):

how do i do that

OpenStudy (anonymous):

?

OpenStudy (anonymous):

im lost

jimthompson5910 (jim_thompson5910):

Factor each term and make sure each term has a factor of 2xy Ex: -16xy = 2xy(-8) Then use the distributive property

OpenStudy (anonymous):

so i got -16xy

OpenStudy (anonymous):

is that correct?

jimthompson5910 (jim_thompson5910):

2x^2y+6x^2y^2-16xy becomes 2xy(x) + 2xy(3xy) + 2xy(-8) What's next?

OpenStudy (anonymous):

would i multiply 2X2 and get 4xy?

jimthompson5910 (jim_thompson5910):

no, use the distributive property

OpenStudy (anonymous):

can u walk me thorugh it?

jimthompson5910 (jim_thompson5910):

use the idea that ab+ac+ad becomes a(b+c+d)

OpenStudy (anonymous):

so how would i combine those up top?

jimthompson5910 (jim_thompson5910):

How can I use the idea given above to factor 2xy(x) + 2xy(3xy) + 2xy(-8)

OpenStudy (anonymous):

distritbutive property

jimthompson5910 (jim_thompson5910):

yes, how can you use that

OpenStudy (anonymous):

by multiplying the coeffients and combining like terms?

OpenStudy (anonymous):

I'm about to have to leave for a hr

jimthompson5910 (jim_thompson5910):

alright, think over what we've done so far

jimthompson5910 (jim_thompson5910):

and read in your book about the distributive property (for how it works and some examples)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

r u going to be on in a hr

jimthompson5910 (jim_thompson5910):

I'm not sure

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I've got about 28 more of these problemes that are due at midnight tonight so im proably going to need help lol

jimthompson5910 (jim_thompson5910):

alright, make sure you read more into it so you get a better understanding of it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

talk to you in a bit :)

jimthompson5910 (jim_thompson5910):

alright

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