Question

Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form

Answer 1

A perpendicular slope, given some slope \[m=\frac{a}{b}\] is:\[m_p=-\frac{b}{a}\]We take the following information and put it into point-slope form:\[(y-y_0)=m(x-x_0)\]\[(y-y_0)=-\frac{1}{4}(x-x_0)\implies (y-2)=-\frac{1}{4}(x-3)\]Solving this in standard form finishes our case.

Answer 2

Thanks but I still don't understand:/

Answer 3

Hmm... all right. So, what do we know about the slope of the line we need to draw?

Answer 4

Well I know I have to use y=mx+ b
-3=(-1/4)(2)+b
-3=-1/2+b
-5/2
giving me...
y=-1/4x-5/2

Then Ax+By=C
y=-1/4x -5/2
y+1/4x=-5/2
4y+x=-10

Is anything wrong in my work??

Answer 5

??

Answer 6

Sorry, I was answering another question. But, yes, you are correct, since the slope is -1/4 and (2, -3) is a point as: \[2+4(-3)=-10\]

Answer 7

No worries! Thank you so very much:D

Answer 8

Sure thing.