Solve Cos^2(5pi/12) using double angle rules. I've looked up double angle rules online but nothing has helped thus far
What double angle identities have you found so far that have cos^2 in them?
Cos^2(theta) - Sin^2(theta) = Cos2(theta)
A quick Google search yields http://www.sosmath.com/trig/douangl/douangl.html The cosine double-angle is the first one listed.
Good. That's the general form; there are two other equivalent identities that cancel out either cos^2 or sin^2 using the Pythagorean identity, cos^2 + sin^2 = 1.
thanks im gonna try it again
I think using \[\cos(2a)=2\cos^2(a)-1\] would be easiest.
If you have a labeled unit circle nearby, it should be pretty easy.
Let me know what you get so I can check my own work. ;-)
Cos^2(5pi/12)-Sin^2(5pi/12)=Cos2(5pi/12)
That will be a difficult equation to use.. The one I recommended would be less of a headache.
Cos(10pie/12) = 2Cos^2(5pi/12)-1
Yes, that'll work. It reduces to:\[\cos^2(5\pi/12)=\frac{1}{2}(1+\cos(5\pi/6)).\]
Cos(10pi/12) would be Cos(5pi/6) which would be equal to negative root 3 /2
Yeah, you should have it from there.
that's not all? I mean I know it has to be either 150 degrees or 210 degrees. What is the next step?
You're not solving for an angle, you're simplifying the expression.
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