Question

help with dividing binomials please

( t^3 - t^2 + t + 1) / (t + 1)

Answer 1

I'd go synthetic on this one.

Answer 2

All your coefficients are either +1 or -1 so polynomial long division would easy enough too, but synthetic division is so much cleaner.

Answer 3

so final answer is t^2-2t+3-(2/t^3-t^2+t+1) right?

Answer 4

i do have t^2 - 2t +3 but i wasnt sure how to get the rest

Answer 5

then since the remainder isnt 0 u hav to divide the remainder by the question so its t^2-2t+3-(2/t^3-t^2+t+1) right? understand?

Answer 6

the parentheses is considered the remainder?

Answer 7

if the remainder was 0 u would leave it like wat u said

Answer 8

yes

Answer 9

ahhh i think i see

Answer 10

but u can write it as a fraction with no paranthesis
the remainder is 2 with the synthetic division but then we divide by thwe question so its like i wrote

Answer 11

thanks i get it

Answer 12

no problemo

Answer 13

Er, there's something wrong there.
You express the remainder as -2 over the divisor, not over the dividend...

Answer 14

( t^3 - t^2 + t + 1) / (t + 1)

Answer 15

Summary
\[
\frac{t^3-t^2+t+1}{t+1}=t^2-2t+3
-\frac{2}{t+1}
\]

Answer 16

@CliffSedge's amswer is correct.\[t^2-2 t+3-\frac{2}{t+1} \]

Answer 17

yes