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Mathematics 4 Online
OpenStudy (anonymous):

Factor: 5x(x-5)+3(x-5)^2

OpenStudy (anonymous):

(5x+3)(x-5)^2

OpenStudy (anonymous):

because 5x and 3 are both multiplied by x-5 you can combine it to 5x+3

OpenStudy (anonymous):

How sure are you that is correct?

OpenStudy (anonymous):

very sure?

OpenStudy (tyteen4a03):

@ShirohxD 's answer is incorrect. (x-5) is the common factor. You should get (x-5)(5x+3(x-5)). After that, expand 3(x-5) and the final answer is (x-5)(8x-15). You can verify answers at Wolfram|Alpha.

OpenStudy (anonymous):

but you distributed

OpenStudy (anonymous):

@ShirohxD please don't respond to anymore of my problems.. you are giving WRONG answers.

OpenStudy (anonymous):

this is a place to help one another, not a place to just get free answers lol

OpenStudy (tyteen4a03):

@ShirohxD If the original equation was \(5x(x-5)^2+3(x-5)^2\), then it would've been correct, however in the equation \(5x(x-5)+3(x-5)^2\), one of the (x-2) has a degree of 2 while the other only has a degree of 1.

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