Question

solve x^-2x-13=0 using quadratic equation from india

Answer 1

from india?

Answer 2

no solutions

Answer 3

i think haha

Answer 4

\[x^2-2x-13=0\]
\[x^2-2x=13\]
\[(x-1)^2=13+1=14\]
\[x-1=\pm\sqrt{14}\]
\[x=1\pm\sqrt{14}\] is easiest method

Answer 5

Quadratic Formula is \[x = \frac{ -b \pm \sqrt{b^2 - 4ac } }{ 2a }\]
I noticed a possible type and assumes that the equation is \(x^2-2x-13=0\).
Just substitute a = 1, b = -2 and c = -13 into this formula.

@satellite73 Indeed it is, but some questions require you to be familiar with the Quadratic Equation.

Answer 6

@satellite73 got it. i just realized i multiplied negative numbers and got a negative answer ??

Answer 7

Wait is there a different way to solve it in india?

Answer 8

because it's from india.

Answer 9

actually "formula from india" only had positive square root. it wasn't until 8th century that al-kwarithimi (whence both the word "al-gorism" and also al-jabr aka "algebra") gave the complete solution

Answer 10

lol if they are not using x equals negetive b plus or minus radical b sqaured minus four a c all over two a then they are not getting the correct roots... hahaha thats all i can say...

Answer 11

\[x ^{2}-2x-13=0\]
\[x ^{2}-2x=13\]
\[x ^{2}-2x+1=13+1\]
\[x ^{2}-2x+1=14\]
Factors Left-
\[(x-1)\times(x-1)=14\]
\[(x-1)^{2}=14\]
\[x-1=\sqrt{14}\]
\[x=\sqrt{14}+1\]